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Posted

If someone could help me out with this it would be a great help, i've got a character who uses electrical attacks only and i need to know the voltage generated by standard guyver's megasmasher. any help would be appreciated

Posted

Volts?! :? Why do you want it rated in volts? To use a plumbing analogy volts is the pressure behind the water. Aren't you more interested in the amount of water? Surely you want Watts (power (Joules/second)), joules(energy (N*m)), or if you continue to use electricity amps. Translating it into joules is easy enough if that is really what you want but I'm not sure how you would express that in volts eVs maybe but just volts, sorry.

Posted (edited)

Zeo1234 really is the one to ask but strangely he doesn't seem to have answered you question. Okay I'll do it. I think together they've been rated to be 0.5 kilotons. Taking Zeo1234's calc from my interesting numbers thread of 1 kiloton=3.795011338*10^12 Joules. It is about 1.897506*10^12 joules. Watts are joules per second. Previously I've timed the firing delay a few times in anime and it was usually about a second. The first episode it being about five seconds. I think you can handle it from there. Feel free to ask if that's not the case.

EDIT: Okay now that its morning again I'll add somethings I really was to tired to yesterday night. Okay 10^12 is Tera watts/joules or whatever unit your using meaning a trillion. As this is a fic and your audience may or may not be familiar with the Tera prefix yet you should probably express it in the presently familiar Giga. So to take the double megasmasher for example it would be expressed as 1,897 Gigajoules. I suppose the problem of epressing it in watts is wattage of what. The cannon itself I think but admitedly am not completely sure should measure either the initial firing delay or refire delay. The beam itself is a diffirent matter. I seem to remember an article about a LASER that was high power/low energy by greatly shortening its pulse but I'm not sure how you'd measure that exactly. Of course, I can tell you the power of the regeneration system with pretty good accuracy.

Edited by Guest
Posted

Barkas remarked in his assessment of the Guyver?s power that the Megasmasher?s energy output "easily exceeded 100 megawatts".

That?s about as much as a small-to-average sized hydro-electric power plant.

Posted

Sorry, I don't always have time to answer questions every day, I gotta work too. :(

Anyway FOG3 is correct and here's some references if you need to convert those numbers.

Energy

1 Btu = 252.0 calories = 1055 joules

1000 joules = 0.9479 Btu

1 joule = 0.2388 calories

1 calorie = 4.187 joules

1 kilowatthour = 3.600 x 106 joules = 3,412 Btu

1 quad = 1015 Btu = 2.931 x 1011 kilowatthours

1 therm = 100,000 Btu

Power

1 watt = 1 joule/sec = 3.412 Btu/hr

1 Btu/hr = 0.2931 watts

1 kilowatt = 0.9478 Btu/sec = 1.341 horsepower

1 Btu/sec = 1.055 kilowatts

1 horsepower = 0.7068 Btu/sec = 0.7457 kilowatts

Basically a Guyver, if the Mega Smashers energy was converted into electricity at 100% efficiency, can release enough energy to supply all of the U.S. energy needs for just under a month or the entire world for about 3-4 days at our present energy consumption rate.

Posted

Wait, I keep finding info the 4.18*10^12 joules figure is correct for a kiloton because it was redefined to be a metric unit and equivelant to a trillion calories link link Dictionary link Given the consistant reaccurance of this figure I don't have much choice but to accept this as the correct figure for a kiloton. Zeo's calc used 1000 US tons so it appears we need to adjust the figures.

So unless WG is using the US complementary system for tons a double megasmasher is 2.09*10^12 joules and a single 1.05*10^12 joules. Divide by two seconds, just to be conservative about it, and we get 1,047 Gigawatts and 524 Gigawatts respectively.

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